What is the moment of inertia of a pendulum with a mass of $4 k g$ $4 kg$ that is $14 m$ $14 m$ from the pivot?

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Answer 1 · 2017-02-23T07:39:31

The moment of inertia is $= 784 k g m^{2}$ $=784kgm^2$

The moment of inertia $I$ $I$ is

$I = m r^{2}$ $I=mr^2$

$= 4 \cdot 14^{2}$ $=4*14^2$

$= 784 k g m^{2}$ $=784kgm^2$

What is the moment of inertia of a pendulum with a mass of 4kg4 kg that is 14m14 m from the pivot?