What is the moment of inertia of a pendulum with a mass of $3 k g$ $3 kg$ that is $9 m$ $9 m$ from the pivot?

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Answer 1 · 2018-03-17T04:41:04

$243 \ "kg m"^2$

Moment of inertia of a simple pendulum is given by:

$I=mr^2$

where $m$ is the mass of the pendulum in kilograms, $r$ is the distance of the pendulum from the pivot in meters.

Plugging in the given values, we get

$I=3 \ "kg"*(9 \ "m")^2$

$=3 \ "kg"*81 \ "m"^2$

$=243 \ "kg m"^2$

What is the moment of inertia of a pendulum with a mass of 3 kg3kg3 kg that is 9 m9m9 m from the pivot?