What is the moment of inertia of a pendulum with a mass of $3 kg$ that is $12 m$ from the pivot?

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Answer 1 · 2018-01-20T06:50:58

$432 Kg.m^2$

Consider the bob of the pendulum to be a point mass as radius is not given.

So moment of inertia of a mass $m$ at a distance of $l$ from a pivoted point is $ml^2$

Given, $m=3Kg$ and $l=12m$

So,its moment of inertia will be $3×(12)^2 Kg.m^2$ or $432 Kg.m^2$

What is the moment of inertia of a pendulum with a mass of 3 kg3 kg that is 12 m12 m from the pivot?