What is the moment of inertia of a pendulum with a mass of 3 kg that is 1 m from the pivot?

1 Answer
Jane
Jan 15, 2018

3 Kg.m^2

Explanation:

Here,you will have to consider that the bob of the pendulum is a point mass,because its radius is not given.

so,the given situation comes out to be that a mass of 3Kg is placed 1 m away from a point,so its moment of inertia w.r.t that point will be mr^2 or 3 Kg.m^2

if,the radius of the bob was given as r,its moment of inertia w.r.t a diameter would be 2/5mr^2 (bob is actually a sphere)

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so,distance between the centre of the bob and the pivoted point would become (1+r)

hence,w.r.t the pivoted point moment of inertia would have been ( 2/5mr^2 + m(1+r)^2)

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