What is the moment of inertia of a pendulum with a mass of $2 kg$ that is $8 m$ from the pivot?

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Answer 1 · 2017-03-06T17:48:02

The moment of inertia is $=128kgm^2$

The moment of inertia of the pendulum is

$I=mr^2$

Where

the mass is $m=2kg$

The distance from the pivot is $r=8m$

The moment of inertia is

$I=mr^2=2*8^2=128kgm^2$

What is the moment of inertia of a pendulum with a mass of 2 kg2 kg that is 8 m8 m from the pivot?