What is the moment of inertia of a pendulum with a mass of 2 kg that is 6 m from the pivot?
1 Answer
Feb 8, 2016
Explanation:
Assumptions:
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You are referring to the moment of inertia about the axis passing through the pivot.
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The pendulum is small enough to be treated as a point mass.
I = MR^2
= (2 "kg") (6 "m")^2
= 72 "kgm"^2
