What is the moment of inertia of a pendulum with a mass of 2 kg that is 1 m from the pivot?

2 Answers
Narad T.
Jun 1, 2017

The moment of inertia is =2kgm^2

Explanation:

We assume that it is a point mass.

The moment of inertia is

I=mr^2

The mass is m=2kg

The distance is r=1m

The moment of inertia is

I=mr^2=2*1^2=2kgm^2

Shreya Naik
Jun 1, 2017

wkt T=2pi* sqrt(l/g)
T= 2pi* sqrt(I/mgd)

Explanation:

So relating both the formulas we get
T=2pi* sqrt(l/g) = 2pi* sqrt(I/mgd)

=> sqrt(l/g) = sqrt(I/mgd) ------( on squaring)
=> (l/g) = (I/mgd)
=>( l*md) = I ------------( g got cancelled)
=> l^2 *m = I ---------------( l and d are same)
=> I= 1*1 * 2 = 2 ------------( hence answer)
...............................hope it helps.........................:)

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