What is the moment of force about point O? (Refer to the image below)

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1 Answer
Harish Chandra Rajpoot
Jul 21, 2018

2490.9696\ \text{lb feet}

Explanation:

Resolving the force of 600\ lb into parallel & vertical components with respect to the axis of given rod/link.

The total torque about the point O in anticlockwise direction,

=(600\ lb)\cos(30^\circ+20^\circ)\times (0.5\ \text{feet})+(600\ lb)\sin(30^\circ+20^\circ)\times (5\ \text{feet})

=600(0.5\cos50^\circ+5\sin50^\circ)\ \text{lb feet}

=2490.9696\ \text{lb feet}

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