What is the molecular formula of a compound with a molar mass of 180.2 grams/mole and the empirical formula $C H_{2} O$ $CH_2O$ ?

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What is the molecular formula of a compound with a molar mass of 180.2 grams/mole and the empirical formula $C H_{2} O$ $CH_2O$ ?

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Answer 1 · 2016-02-09T16:42:05

The molecular formula is ALWAYS a whole number multiple of the empirical formula.

Explanation:

Thus $MOLECULAR FORMULA$ $"MOLECULAR FORMULA"$ $=$ $=$ $(EMPIRICAL FORMULA) \times n$ $("EMPIRICAL FORMULA")xxn$ .

So $180.2 \cdot g \cdot m o l^{- 1} = n \times (12.011 + 2 \times 1.00794 + 15.999) \cdot g \cdot m o l^{- 1} = 30 \times n$ $180.2*g*mol^-1=nxx(12.011 +2xx1.00794+15.999)*g*mol^-1 = 30xxn$ .

$n = 6$ $n=6$ , and $MOLECULAR FORMULA$ $"MOLECULAR FORMULA"$ $=$ $=$ $6 \times (C H_{2} O) = C_{6} H_{12} O_{6}$ $6xx(CH_2O) = C_6H_12O_6$ .

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What is the molecular formula of a compound with a molar mass of 180.2 grams/mole and the empirical formula $C H_{2} O$ $CH_2O$ ?

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What is the molecular formula of a compound with a molar mass of 180.2 grams/mole and the empirical formula $C H_{2} O$ $CH_2O$ ?