What is the molecular formula if the empirical formula is $C_{3} H_{7}$ $C_3H_7$ , and the experimental molar mass is 86 g/mole?

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Answer 1 · 2016-05-31T04:22:15

$C_{6} H_{14}$ $C_6H_14$

Brute force method:

in this case:
C=12.01
N=14
H=1.008

the empirical formula adds up to 43g/mol
multiply by two, we get 86g/mol

What is the molecular formula if the empirical formula is C_3H_7C3H7C_3H_7, and the experimental molar mass is 86 g/mole?