What is the mole fraction of solute in a 3.89 m aqueous solution?

1 Answer
anor277
Dec 13, 2016

#"Molality"# #=# #"Moles of solute"/"Kilograms of solvent"#

#chi=(3.89*mol)/(3.89*mol+(1000*g)/(18.01*g*mol^-1))=0.067#

Explanation:

And #chi,# #"mole fraction"# #=# #"Moles of solute"/"Moles of solute and moles of solvent"#

We have a #3.89# #"molal"# solution (at least I think we do); i.e. #"molality"# #=# #3.89*mol*kg^-1#.

And thus #chi=(3.89*mol)/(3.89*mol+(1000*g)/(18.01*g*mol^-1))=0.067#

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