What is the mole fraction of solute in a 3.89 m aqueous solution? Chemistry Stoichiometry Mole Ratios 1 Answer anor277 Dec 13, 2016 #"Molality"# #=# #"Moles of solute"/"Kilograms of solvent"# #chi=(3.89*mol)/(3.89*mol+(1000*g)/(18.01*g*mol^-1))=0.067# Explanation: And #chi,# #"mole fraction"# #=# #"Moles of solute"/"Moles of solute and moles of solvent"# We have a #3.89# #"molal"# solution (at least I think we do); i.e. #"molality"# #=# #3.89*mol*kg^-1#. And thus #chi=(3.89*mol)/(3.89*mol+(1000*g)/(18.01*g*mol^-1))=0.067# Answer link Related questions Question #a106e Question #e2e86 Question #a1072 Question #c5bf1 Question #dc373 Question #c5bf9 Question #a1076 Question #dc377 Question #b984f Question #19ea3 See all questions in Mole Ratios Impact of this question 60845 views around the world You can reuse this answer Creative Commons License