What is the molar volume of 3.01 x 10(23) molecules of ethane (C2H6)?

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Answer 1 · 2014-06-28T15:46:52

One mole of any gas at STP takes up 22.4 L of volume.

one mole of gas = 22.4 L ..... (a)

one mole of gas has 6.02 x #10^ 23# particles( Molecules) ..... (b)

equating (a) and (b) we get

6.022 x #10^ 23# particles (Molecules) = 22.4 L

Making conversion factors 22.4 L / 6.02 x #10^ 23# particles or

6.02 x #10^ 23# particles / 22.4 L

since we want change the # of molecules into L we will use the conversion factor that when multiplied by the given number
gives L as the final unit.

3.01 x #10^23# particles x 22.4 L / 6.02 x #10^ 23# particles

11.2 L