What is the mol solute and volume solution of #C_12H_22O_11# which has the solute mass 55.38 g and the molarity 0.150 mol/L?

1 Answer
anor277
Apr 24, 2018

We use the relationship...... there are #0.162*mol# of sucrose... and get a volume of solvent over #1*L#.

Explanation:

We use the relationship...

#"Concentration"="Moles of solute"/"Volume of solution"#

And so #"moles of solute"="concentration"xx"volume"#

#((55.38*g)/(342.3 *g*mol^-1))/("volume of solution")=0.150*mol*L^-1#

And #"volume of solution"=((55.38*g)/(342.3 *g*mol^-1))/(0.150*mol*L^-1)=1.079*L#

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