What is the mol solute and volume solution of C_12H_22O_11C12H22O11 which has the solute mass 55.38 g and the molarity 0.150 mol/L?

1 Answer
Apr 24, 2018

We use the relationship...... there are 0.162*mol0.162mol of sucrose... and get a volume of solvent over 1*L1L.

Explanation:

We use the relationship...

"Concentration"="Moles of solute"/"Volume of solution"Concentration=Moles of soluteVolume of solution

And so "moles of solute"="concentration"xx"volume"moles of solute=concentration×volume

((55.38*g)/(342.3 *g*mol^-1))/("volume of solution")=0.150*mol*L^-155.38g342.3gmol1volume of solution=0.150molL1

And "volume of solution"=((55.38*g)/(342.3 *g*mol^-1))/(0.150*mol*L^-1)=1.079*Lvolume of solution=55.38g342.3gmol10.150molL1=1.079L