What is the mol solute and volume solution of C_12H_22O_11C12H22O11 which has the solute mass 55.38 g and the molarity 0.150 mol/L?

1 Answer
anor277
Apr 24, 2018

We use the relationship...... there are 0.162*mol0.162⋅mol of sucrose... and get a volume of solvent over 1*L1⋅L.

Explanation:

We use the relationship...

"Concentration"="Moles of solute"/"Volume of solution"Concentration=Moles of soluteVolume of solution

And so "moles of solute"="concentration"xx"volume"moles of solute=concentration×volume

((55.38*g)/(342.3 *g*mol^-1))/("volume of solution")=0.150*mol*L^-155.38⋅g342.3⋅g⋅mol−1volume of solution=0.150⋅mol⋅L−1

And "volume of solution"=((55.38*g)/(342.3 *g*mol^-1))/(0.150*mol*L^-1)=1.079*Lvolume of solution=55.38⋅g342.3⋅g⋅mol−10.150⋅mol⋅L−1=1.079⋅L

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