What is the mol solute and volume solution of $C_12H_22O_11$ which has the solute mass 55.38 g and the molarity 0.150 mol/L?

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Answer 1 · 2018-04-24T07:24:57

We use the relationship...... there are $0.162*mol$ of sucrose... and get a volume of solvent over $1*L$ .

We use the relationship...

$"Concentration"="Moles of solute"/"Volume of solution"$

And so $"moles of solute"="concentration"xx"volume"$

$((55.38*g)/(342.3 *g*mol^-1))/("volume of solution")=0.150*mol*L^-1$

And $"volume of solution"=((55.38*g)/(342.3 *g*mol^-1))/(0.150*mol*L^-1)=1.079*L$

What is the mol solute and volume solution of C_12H_22O_11C_12H_22O_11 which has the solute mass 55.38 g and the molarity 0.150 mol/L?