What is the maximum value that the graph of $y = x^{2} - 4 x$ $y= x^2 -4x$ ?

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What is the maximum value that the graph of $y = x^{2} - 4 x$ $y= x^2 -4x$ ?

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Answer 1 · 2016-10-06T13:56:30

There is no maximum.

Explanation:

As $x$ $x$ increases without bound, $x^{2} - 4 x$ $x^2-4x$ also increases without bound. (Another way of saying this is: $lim_(xrarroo)(x^2-4x) = oo$ .) That means there is no upper bound and no maximum.

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What is the maximum value that the graph of $y = x^{2} - 4 x$ $y= x^2 -4x$ ?

1 Answer

Explanation:

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What is the maximum value that the graph of y= x^2 -4xy=x2−4xy= x^2 -4x?

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What is the maximum value that the graph of $y = x^{2} - 4 x$ $y= x^2 -4x$ ?