What is the maximum value that the graph of #y= x^2 -4x#?

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What is the maximum value that the graph of #y= x^2 -4x#?

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Answer 1 · 2016-10-06T13:56:30

There is no maximum.

Explanation:

As #x# increases without bound, #x^2-4x# also increases without bound. (Another way of saying this is: #lim_(xrarroo)(x^2-4x) = oo#.) That means there is no upper bound and no maximum.

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What is the maximum value that the graph of #y= x^2 -4x#?

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