What is the maximum value of #y=-3sinx+2#?

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Answer 1 · 2017-10-11T17:06:22

#5#

For: #y=-3sinx+2#

Since #sinx# is multiplied by a negative value, we want #sinx# to be a minimum value.

#0<=x<=2pi#

#-1<= sinx<=1#

Maximum value:

If #x= (3pi)/2#. then #sinx= -1# and #-3sinx+2=5#

Graph:

graph{-3sinx+2 [-12.66, 12.65, -6.33, 6.33]}