What is the maximum value of 5sin(t) + 12cos(t)?

1 Answer
May 6, 2016

The maximum is 13 and minimum is -13.

Explanation:

f(t)= 5 sin t + 12 cos t. We can compound these two oscillations into a single sine oscillation.

f(t) = 13((5/13) sin t + (12/13) cos t)

= 13 (cos b sin t + sin b cost )

= 13 sin ( t + b ), where sin b =12/13 and cos b = 5/13.

So, -13 <= f(t) = 13 sin ( t + b ) <=13

The amplitude of the oscillation is 13 and the period is 2pi..