What is the mass of 6.02 * 10^23 atoms of calcium?

1 Answer
anor277
Jun 25, 2016

In 1 mol of Ca "atoms", there are N_A individual calcium atoms.

Explanation:

How does this help you? Well, it happens that N_A, "Avogadro's Number" ~= 6.022xx10^23*mol^-1.

And it is stated on your trusty Periodic Table that the molar mass of Ca is 40.08*g*mol^-1. So, if we specify a molar quantity, we specify a precise number of atoms and molecules that can be approximated by mass.

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