What is the mass of $4.22 x 10^{23}$ $4.22 x 10^23$ atoms of lead?

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What is the mass of $4.22 x 10^{23}$ $4.22 x 10^23$ atoms of lead?

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Answer 1 · 2017-04-10T14:22:05

145.2

Explanation:

1 mole ( $6.022 \cdot 10^{23}$ $6.022*10^(23)$ molecules ) weigh 207.2 gm
for $4.22 \cdot 10^{23}$ $4.22*10^(23)$ molecules weight weight $\Rightarrow$ $=>$
$\frac{4.22 \cdot 10^{23}}{6.022 \cdot 10^{23}} \cdot 207.2 = 145.2 g$ $(4.22*10^(23))/(6.022*10^(23))*207.2=145.2g$

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What is the mass of $4.22 x 10^{23}$ $4.22 x 10^23$ atoms of lead?

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