What is the mass of 19.42 atoms of F?

1 Answer
Aug 26, 2016

Well 6.022xx10^23 atoms of fluorine (as the atom, not as F_2) have a mass of 19.00*g.

Explanation:

And thus 19/(6.022xx10^23*mol^-1)xx19.00*g*mol^-1

= "not too many grams".

We cannot really speak of 0.42*"atoms" of fluorine. We can have the one atomic particle; we cannot really have 1/2 of an atom.