What is the mass of $1.7 times 10^23$ atoms of zinc?

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Answer 1 · 2017-07-30T19:14:37

Approx. $20*g$ ........

$6.022xx10^23$ individual zinc atoms have a mass of $65.39*g$ , and thus to get the mass of $1.7xx10^23*"zinc atoms"$ have a mass of......

$(1.7xx10^23*"zinc atoms")/(6.022xx10^23*"zinc atoms"*mol^-1)xx65.39*g*mol^-1=?*g$

From where did I get the number $6.022xx10^23$ ? Is this in any way special?

What is the mass of 1.7 times 10^231.7 times 10^23 atoms of zinc?