What is the mass of 1.39 mol of $MgO$ ?

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Answer 1 · 2016-02-14T00:18:26

$1$ $mol$ of magnesium oxide has a mass of $40.30$ $g*mol^-1$

So the required mass is $1.39$ $cancel(mol)$ $xx$ $40.30$ $g*cancel(mol^-1)$ $=$ $??$ $g$ .

What is the mass of 1.39 mol of MgOMgO?