What is the mass in grams of 7.9×1021 uranium atoms?

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1 Answer
anor277
Nov 25, 2017

Well what is the mass of Avogadro's Number of uranium atoms?

Explanation:

A quick glimpse at the Periodic Table gives the molar mass of uranium as 231.8⋅g⋅mol−1.

Now, by definition, this mass is equivalent to the mass of Avogadro's Number of uranium atoms. And so to get the mass of the specified number, we take the product of the quotient:

7.9×1021⋅uranium atoms6.022×1023⋅uranium atoms⋅mol−1×231.8⋅g⋅mol−1

And my calculator says that this represents approx. a 3⋅g mass....

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