What is the limiting reagent when 3.10 mol of #SO_2# reacts with 2.75 mol of #O_2# according to the equation: #SO_2 + O_2 -> SO_3#?

1 Answer
anor277
Jun 8, 2016

Your equation is incorrect; it is not stoichiometrically balanced.

Explanation:

Synthesis of sulfur trioxide is represented stoichiometrically:

#SO_2(g) + 1/2O_2(g) rarr SO_3(g)#

This equation tells us that #64*g# of sulfur dioxide reacts with #16# dioxygen gas to give #80*g# of sulfur trioxide.

Clearly, given this equation, there is excess dioxygen gas. The given molar quantity of sulfur dioxide requires only #1.6*mol# dioxygen gas.

You will have to calculate the mass of product yourself.

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