What is the limit of #(x^2 - 7x)/(x+1)# as x goes to infinity?

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What is the limit of #(x^2 - 7x)/(x+1)# as x goes to infinity?

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Answer 1 · 2015-10-17T14:19:47

I would say #oo#:

Explanation:

Consider:
#lim_(x->oo)((x^2-7x)/(x+1))=# collecting #x^2# and #x#:
#lim_(x->oo)((x^cancel(2)(1-7/x))/(cancel(x)(1+1/x)))=#
as #x->oo# then #1/x^n->0# so:
#(oo(1-0))/(1+0)=oo#

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What is the limit of #(x^2 - 7x)/(x+1)# as x goes to infinity?

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