What is the length of the hypotenuse of a right triangle if the two other sides are of lengths 6 and 2?

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Answer 1 · 2018-06-30T17:22:30

$2 \sqrt{10}$ $2sqrt(10)$

By the Theorem of Pythagorean
$c^{2} = a^{2} + b^{2}$ $c^2=a^2+b^2$

we get

$c^{2} = 4 + 36$ $c^2=4+36$
so
$c = \sqrt{40} = \sqrt{4 \cdot 10} = 2 \sqrt{10}$ $c=sqrt(40)=sqrt(4*10)=2sqrt(10)$

Answer 2 · 2018-06-30T17:27:08

The length of hypotenuse $= c = 2 \sqrt{10} \approx 6.32$ $=c=2sqrt10~~6.32$

Let $△ A B C$ $triangle ABC$ be the right triangle.

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Let , $¯ ¯¯¯¯ ¯ A B$ $bar(AB)$ be the hypotenuse and $m ∠ C = \frac{π}{2}$ $m /_C=pi/2$

Let , $B C = a = 2 and A C = b = 6 and A B = c$ $BC=a=2 and AC=b=6 and AB=c$

We know that,

$c^{2} = a^{2} + b^{2}$ $c^2=a^2+b^2$

$\Rightarrow c^{2} = 2^{2} + 6^{2} = 4 + 36 = 40$ $=>c^2=2^2+6^2=4+36=40$

$\Rightarrow c^{2} = 4 \times 10$ $=>c^2=4xx10$

$\Rightarrow c = 2 \sqrt{10} \approx 6.32$ $=>c=2sqrt10~~6.32$