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What is the inverse of #y= log_2(2x)# ?

1 Answer

Oct 27, 2015

I found: #y=2^(x-1)#

Explanation:

You can use the definition of log:
(#log_ax=b->x=a^b#) and get:

#2x=2^y#

so that:
#x=2^y/2=2^y/2^1=2^(y-1)#
That we can write:
#color(red)(y=2^(x-1))#

graph{2^(x-1) [-11.25, 11.245, -5.63, 5.62]}

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