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What is the interval of convergence of #sum_1^oo ln(n)/e^n (x-e)^n #?

1 Answer

Jan 28, 2017

#abs((x-e)/e)<1#

Explanation:

#((x-e)/e)^n < log(n)((x-e)/e)^n <(n+1)((x-e)/e)^n=ed/(dx)((x-e)/e)^(n+1) #

so the series is convergent for

#abs((x-e)/e)<1#

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