What is the integral of #xe^2x dx#?

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What is the integral of #xe^2x dx#?

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Answer 1 · 2015-02-17T17:49:02

I am not sure that your integrand is right because you can simply write it as #e^2*x^2dx# and it can be integrated as (#e^2# is a constant):
#inte^2*x^2dx=e^2intx^2dx=e^2x^3/3+c#

On the other hand, it can be:
#intx*e^(2x)dx=# which can be solved By Parts:
#=x*e^(2x)/2-int1*e^(2x)/2dx=#
#=xe^(2x)/2-e^(2x)/4+c#

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What is the integral of #xe^2x dx#?

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