What is the $[H^+]$ of a solution with a pH of 6.6?

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Answer 1 · 2016-06-17T18:18:48

$[H^+]=10^(-6.6)$ $mol*L^-1$

$pH=-log_10[H^+]$ by definition.

If $pH=6.6$ , then to get $[H^+]$ we take the antilogarithm:

$[H^+]$ $=$ $10^(-6.6)$ $mol*L^-1$ with respect to $H^+$ or $H_3O^+$ , an equivalent representation.

This solution is very slightly acidic. I don't think you could taste the difference.

What is the [H^+][H^+] of a solution with a pH of 6.6?