What is the gram-formula mass of #(NH_4)_3PO_4#?

1 Answer
Meave60
Jul 10, 2018

It is #"149.087 g/mol"#.

Explanation:

Multiply the subscript for each element by its molar mass, which is its atomic weight in g/mol. In the case of #("NH"_4)_3"#, multiply the subscripts inside the parentheses by #3#.

Gram-formula mass of #("NH"_4)_3"PO"_4"#

#(3xx"14.007 g/mol N") + (12xx"1.008 g/mol H") + (1xx"30.974 g/mol P") + (4xx"15.999 g/mol O")=#

#"149.087 g/mol"# #("NH"_4)_3"PO"_4"#

Related questions
See all questions in Atomic Mass
Impact of this question
14169 views around the world
You can reuse this answer
Creative Commons License