What is the force, in terms of Coulomb's constant, between two electrical charges of #-6 C# and #-16 C# that are #9 m # apart?

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Answer 1 · 2018-06-12T13:29:39

I get approximately #10.7k#.

#F=k(q_1q_2)/r^2#

where:

#k# is Coulomb's constant

#q_1,q_2# are charges of the two charges in coulombs

#r# is the distance between the charges in meters

So, we get:

#F=k(-6*-16)/9#

#~~10.7k#

Answer 2 · 2018-06-12T13:42:01

#F~~1.0652*10^10 N#

Coulomb's Law with Coulomb's constant:

#F=(kQ_1Q_2)/r^2#

We will assume that the charges occur in a vacuum.

#k= 8.988*10^9 (Nm^2)/C^2#
#Q_1=-6 C#
#Q_2=-16 C#
#r=9 m#

#F=(( 8.988*10^9)(-6)(-16))/9^2#

#F~~1.0652*10^10 N#