What is the factored form of $a^2+12a−108$ ?

Question

1289 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-08T17:44:26

$(a+18)(a-6)$

$"the factors of - 108 which sum to + 12 are + 18 and - 6"$

$a^2+12a-108=(a+18)(a-6)$

Answer 2 · 2018-06-08T17:46:22

$(x+18)(x-6)$

To factor find 2 number who's sum is 12 and product is -108:

$18 * -6 = -108$

$18 -6 = 12$

$a^2+12a−108$

$(x+18)(x-6)$

What is the factored form of a^2+12a−108a^2+12a−108?