What is the factored form of #a^2+12a−108#?

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Answer 1 · 2018-06-08T17:44:26

#(a+18)(a-6)#

#"the factors of - 108 which sum to + 12 are + 18 and - 6"#

#a^2+12a-108=(a+18)(a-6)#

Answer 2 · 2018-06-08T17:46:22

#(x+18)(x-6)#

To factor find 2 number who's sum is 12 and product is -108:

#18 * -6 = -108#

#18 -6 = 12#

#a^2+12a−108#

#(x+18)(x-6)#