What is the exact value of $tan ^2 45+ sec ^2 30$ ?

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Answer 1 · 2015-06-11T09:27:10

Answer is 7/3.

$tan^2(45)+sec^2(30)=1^2+(2/sqrt(3))^2$ [From trig.angle table]
$=1+4/3$
$=7/3$
$=2.3333333333$

Which is required solution.

What is the exact value of tan ^2 45+ sec ^2 30tan ^2 45+ sec ^2 30?