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What is the exact value of #sin 60 - cos 60#?

1 Answer

Jun 24, 2015

#sin(60°)-cos(60°)=(sqrt3-1)/2#

Explanation:

The exact values of #cos(60°)# and #sin(60°)# are:
#cos(60°)=cos(pi/3)=1/2#
#sin(60°)=sin(pi/3)=sqrt3/2#

#rarr sin(60°)-cos(60°)=sqrt3/2-1/2=(sqrt3-1)/2#

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