What is the equation of the parabola that has a vertex at # (-2, -5) # and passes through point # (2,6) #?

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What is the equation of the parabola that has a vertex at # (-2, -5) # and passes through point # (2,6) #?

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Answer 1 · 2017-04-19T11:11:56

The equation of parabola is #y = 11/16(x+2)^2 -5#

Explanation:

Vertex # (h= -2,k= -5) # The equation of parabola is #y=a(x-h)^2+k or y = a(x+2)^2 -5#
The point #(2,6)# lies on parabola. # :. 6 = a*(2+2)^2 -5 or 16a =11 or a =11/16#
Hence the equation of parabola is #y = 11/16(x+2)^2 -5# graph{11/16(x+2)^2-5 [-10, 10, -5, 5]}[Ans]

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What is the equation of the parabola that has a vertex at # (-2, -5) # and passes through point # (2,6) #?

1 Answer

Explanation:

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