What is the equation of the parabola that has a vertex at # (-15, -4) # and passes through point # (15,5) #?

1 Answer
May 2, 2017

#y=1/100(x+15)^2-4#

Explanation:

The equation of a parabola in #color(blue)"vertex form"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(y=a(x-h)^2+k)color(white)(2/2)|)))#
where (h , k) are the coordinates of the vertex and a is a constant.

#"here " (h,k)=(-15,-4)#

#rArry=a(x+15)^2-4#

#"to find a use the point that parabola passes through" #

#"using " (15,5)" that is x = 15 and y = 5"#

#rArr5=a(15+15)^2-4#

#rArr900a=9rArra=1/100#

#rArry=1/100(x+15)^2-4larrcolor(red)" in vertex form"#
graph{1/100(x+15)^2-4 [-20, 20, -10, 10]}