What is the equation of the line passing through #(93,78)# and #(-68,44)#?

1 Answer
mason m
Nov 14, 2015

Find the line in the form #y = mx + b#.
The slope can be found through the formula #m=(y_2-y_1)/(x_2-x_1)#.
Thus, #color(red)(m)=(44-78)/(-68-93)=(-34)/-161=color(red)(34/161)#

Now, find #b# by plugging #m# into #y = mx + b# with one of the points.

With the point #(93,78)#: #78 = (34/161)93+b#
Multiply: #78 = 3162/161+b#
Find a common denominator: #12558/161=3162/161+b#
Subtract #3162/161# from both sides: #color(red)(9396/161=b)#
This cannot be simplified.

Plug back into #y=mx+b#: #color(red)(y=34/(161)x+9396/161)#

This can also be written as #y=(34x+9396)/161#

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