What is the equation of the line passing through (93,78) and (-68,44)?

1 Answer
mason m
Nov 14, 2015

Find the line in the form y = mx + b.
The slope can be found through the formula m=(y_2-y_1)/(x_2-x_1).
Thus, color(red)(m)=(44-78)/(-68-93)=(-34)/-161=color(red)(34/161)

Now, find b by plugging m into y = mx + b with one of the points.

With the point (93,78): 78 = (34/161)93+b
Multiply: 78 = 3162/161+b
Find a common denominator: 12558/161=3162/161+b
Subtract 3162/161 from both sides: color(red)(9396/161=b)
This cannot be simplified.

Plug back into y=mx+b: color(red)(y=34/(161)x+9396/161)

This can also be written as y=(34x+9396)/161

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