What is the equation of the line passing through $(93, 78)$ $(93,78)$ and $(- 68, 44)$ $(-68,44)$ ?

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What is the equation of the line passing through $(93, 78)$ $(93,78)$ and $(- 68, 44)$ $(-68,44)$ ?

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Answer 1 · 2018-04-14T22:25:42

The slope is $\frac{122}{161}$ $122/161$ .

Explanation:

$(93, 78)$ $(93, 78)$ and $(- 68, 44)$ $(-68, 44)$
Slope of a line is defined by $\frac{change in y}{change in x}$ $"change in y"/"change in x"$ or $\frac{rise}{run}$ $"rise"/"run"$ or the formula $\frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ $(y_2-y_1)/(x_2-x_1)$ .

We have the value of two points, so we can plug them into the formula:
$\frac{- 44 - 78}{- 68 - 93}$ $(-44-78)/(-68-93)$

Simplify...
$\frac{- 122}{- 161}$ $(-122)/(-161)$

$\frac{122}{161}$ $122/161$

The slope is $\frac{122}{161}$ $122/161$ .

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What is the equation of the line passing through $(93, 78)$ $(93,78)$ and $(- 68, 44)$ $(-68,44)$ ?

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Explanation:

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What is the equation of the line passing through (93,78)(93,78) and (−68,44)(-68,44)?

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What is the equation of the line passing through $(93, 78)$ $(93,78)$ and $(- 68, 44)$ $(-68,44)$ ?