What is the equation of the line passing through #(51,2)# and #(14,56)#?

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Answer 1 · 2018-04-07T02:20:35

#color(indigo)(37y + 54x = 2828#

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Given #(x_1, y_1) = (51, 2), (x_2, y_2) = (14, 56)#

#m = (y_2 - y_1) / (x_2 - x_1) = (56 - 2) / (14-51) = -54/37#

Equation of the line is #(y - y_1) = m * (x - x_1)#

#(y - 2) = -(54/37) * (x - 51)#

#37y - 74 = -54x + 2754#

#37y + 54x = 2754 + 74 = 2828#