What is the equation of the line passing through #(3,-4)# and #(-5,-1)#?

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Answer 1 · 2016-12-18T17:17:12

4x + 8y + 20 = 0

we know equation of a line passing through #(x_1,y_1) and (x_2, y_2)#

=# [y-y_1]/[x-x_1] = [y_2-y_1]/[x_2-x_1]#

So equation of line passing through (3, -4) and (-5, -1) =

#[y-(-4)]/[x-3] = [-1-(-4)]/[-5-3]#

or, #[y+4]/[x-3] = [-1+5]/[-8] #

or, #-8(y+4) = 4(x-3)#

or,#-8y-32 = 4x-12#

or, 4x + 8y + 32 - 12 = 0

or, 4x + 8y + 20 = 0