What is the equation of the line passing through $(2, 6), (1, 6)$ $(2,6), (1,6)$ ?

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What is the equation of the line passing through $(2, 6), (1, 6)$ $(2,6), (1,6)$ ?

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Answer 1 · 2016-01-14T00:58:22

$y = 6$ $y=6$

Explanation:

Let -

$x_{1} = 2$ $x_1=2$
$y_{1} = 6$ $y_1=6$
$x_{2} = 1$ $x_2=1$
$y_{2} = 6$ $y_2=6$

Then the equation of the line is -

$(y - y_{1}) = \frac{y_{2} - y_{1}}{x_{2} - x_{1}} (x - x_{1})$ $(y-y_1)=(y_2-y_1)/(x_2-x_1)(x-x_1)$
$y - 6 = \frac{6 - 6}{1 - 2} (x - 2)$ $y-6=(6-6)/(1-2)(x-2)$
$y - 6 = \frac{0}{- 1} (x - 2)$ $y-6=0/-1(x-2)$
$y - 6 = 0$ $y-6=0$
$y = 6$ $y=6$

On observation you can have an idea about the equation.

It is a linear equation.
Its x-co-ordinate is varying.
Its y co-ordinate is the same.

Hence it is a straight line parallel to the x - axis.

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What is the equation of the line passing through $(2, 6), (1, 6)$ $(2,6), (1,6)$ ?

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