What is the equation of the line passing through #(2,6), (1,6)#?

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Answer 1 · 2016-01-14T00:58:22

#y=6#

Let -

#x_1=2#
#y_1=6#
#x_2=1#
#y_2=6#

Then the equation of the line is -

#(y-y_1)=(y_2-y_1)/(x_2-x_1)(x-x_1)#
#y-6=(6-6)/(1-2)(x-2)#
#y-6=0/-1(x-2)#
#y-6=0#
#y=6#

On observation you can have an idea about the equation.

It is a linear equation.
Its x-co-ordinate is varying.
Its y co-ordinate is the same.

Hence it is a straight line parallel to the x - axis.