# What is the equation of the line passing through #(-2,2)# and #(-1,-2)#?

##### 1 Answer

Your answer must be in the form of *y=mx+b*

#### Explanation:

To find the equation of this line, first write out slope-intercept form:

y=mx+b

m is the slope, and b is the y intercept. In your final equation, you will leave x and y as x and y.

The first thing to do is find the slope. We know the equation for this is (Change in y)/(Change in x). Therefore the slope would equal

(-2-2)/(-1-(-2)).

I assume you understand how to calculate slope. Simplified, that gives us

-4/1

or -4

Now that we know the slope, our equation looks like this (since slope is m)

y=-4x+b

All we have to do now is find b, or the y intercept. To do this, we simply take one of the coordinates (we'll use the first one) and plug in -2 for x and 2 for y (the x and y points).

Your equation will look like:

(2)=-4(-2)+b

Solve for b. You should get b equal to -6.

Put that in for b and your final equation looks like this:

y=-4x-6