What is the equation of the line passing through #(-2,13)# and #(0,-2)#?

1 Answer
Jim G.
Apr 15, 2018

#y=-15/2x-2#

Explanation:

#"the equation of a line in "color(blue)"slope-intercept form"# is.

#•color(white)(x)y=mx+b#

#"where m is the slope and b the y-intercept"#

#"to calculate m use the "color(blue)"gradient formula"#

#•color(white)(x)m=(y_2-y_1)/(x_2-x_1)#

#"let "(x_1,y_1)=(-2,13)" and "(x_2,y_2)=(0,-2)#

#rArrm=(-2-13)/(0-(-2))=(-15)/2=-15/2#

#rArry=-15/2x+blarrcolor(blue)"is the partial equation"#

#"to find b substitute either of the 2 given points into"#
#"the partial equation"#

#"using "(0,-2)" then"#

#-2=0+brArrb=-2#

#rArry=-15/2x-2larrcolor(red)"is the equation of the line"#

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