What is the equation of the line passing through #(11,14)# and #(35,12)#?

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What is the equation of the line passing through #(11,14)# and #(35,12)#?

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Answer 1 · 2018-03-17T02:47:24

#x+12y-179=0#

Explanation:

Let #(11,14)# be #(x_1,y_1)# and #(35,12)# be #(x_2,y_2)#.
The equation for a straight line passing through two points is,
#y-y_1=(y_2-y_1)/(x_2-x_1) xx( x-x_1)#
Substitute the respective values,
#y-14=(12-14)/(35-11) xx( x-11)#
#y-14=-2/24 xx( x-11)#
#y-14=-1/12 xx( x-11)#
#12(y-14)=-1 xx( x-11)#
#12y-168=-x+11#
#x+12y-179=0#

That's it.
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What is the equation of the line passing through #(11,14)# and #(35,12)#?

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