What is the equation of the line between #(-3,-3)# and #(-7,1)#?

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What is the equation of the line between #(-3,-3)# and #(-7,1)#?

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Answer 1 · 2015-11-20T12:09:36

I found:
#4x+4y+24=0#
or:
#y=-x-6# in Slope-Intercept form.

Explanation:

You can try a relationship such as:
#(x-x_2)/(x_2-x_1)=(y-y_2)/(y_2-y_1)#
Where you use the coordinates of your points #P_1# and #P_2# as:
#(x-(-7))/(-7-(-3))=(y-1)/(1-(-3))#
#(x+7)/(-7+3)=(y-1)/(1+3)#
#(x+7)/-4=(y-1)/4# rearranging:
#4x+28=-4y+4#
so:

#4x+4y+24=0#
or:
#y=-x-6#

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What is the equation of the line between #(-3,-3)# and #(-7,1)#?

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