What is the equation of the line between (3,-2)(3,−2) and (-5,1)(−5,1)?

1 Answer
Roella W.
Nov 19, 2015

A line equation is of the form y=ax+by=ax+b. By substituting in the values from the two points, the equations can be solved by substitution to get the values of a and b

Explanation:

-2 = a*3 + b−2=a⋅3+b
Therefore b = -2 -a*3b=−2−a⋅3
1 = a*-5 +b1=a⋅−5+b
Therefore b = 1 + a*5b=1+a⋅5
-2 - 3*a = 1 + 5*a−2−3⋅a=1+5⋅a
8*a = -38⋅a=−3
a = -3/8a=−38
b = -2 - (-3/8)*3b=−2−(−38)⋅3
b = -2 +9/8b=−2+98
b = -7/8b=−78
y = (-3/8)*x + (-7/8)y=(−38)⋅x+(−78)
8*y = -3*x - 78⋅y=−3⋅x−7

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