What is the equation of the line between #(-20,2)# and #(7,-8)#?

1 Answer
Binayaka C.
Mar 30, 2017

The equation of the line in standard form is # 10x +27y = -146#

Explanation:

The slope of the line passing through #(-20,2) and (7,-8)# is #m= (y_2-y_1)/(x_2-x_1)= (-8-2)/(7+20)=-10/27#

Let the equation of the line in slope-intercept form be #y=mx+c or y=-10/27x+c# The point (-20,2) will satisfy the equation . So, # 2= -10/27*(-20)+c or c= 2-200/27= -146/27#

Hence the equation of the line in slope-intercept form is #y= -10/27x-146/27.#

The equation of the line in standard form is #y= -10/27x-146/27. or 27y =-10x-146 or 10x +27y = -146# {Ans]

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