What is the equation of the line between #(-11,4)# and #(7,-7)#?

1 Answer
Binayaka C.
Mar 31, 2017

The equation of the line in standard form is # 11x +18y = -49#

Explanation:

The slope of the line passing through #(-11,4) and (7,-7)# is #m= (y_2-y_1)/(x_2-x_1)= (-7-4)/(7+11)= -11/18#

Let the equation of the line in slope-intercept form be #y=mx+c or y=-11/18x+c# The point (-11,4) will satisfy the equation . So, # 4= -11/18*(-11)+c or c= 4-121/18= -49/18#

Hence the equation of the line in slope-intercept form is #y= -11/18x-49/18.#

The equation of the line in standard form is #y= -11/18x-49/18. or 18y =-11x-49 or 11x +18y = -49# {Ans]

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