What is the equation of circle with center at (0,0) and radius of 7?

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Answer 1 · 2016-01-26T20:55:37

#x^2+y^2=49#

The standard form of a circle with a center at #(h,k)# and a radius #r# is

#(x-h)^2+(y-k)^2=r^2#

Since the center is #(0,0)# and the radius is #7#, we know that

#{(h=0),(k=0),(r=7):}#

Thus, the equation of the circle is

#(x-0)^2+(y-0)^2=7^2#

This simplifies to be

#x^2+y^2=49#

graph{(x^2+y^2-49)=0 [-16.02, 16.03, -8.01, 8.01]}