What is the equation in standard form of the parabola with a focus at (1,5) and a directrix of y= 7?

1 Answer
Feb 16, 2016

y=14x2+12x+236

Explanation:

Focus is at (1,5) and directrix is y=7. So the distance between focus and directrix is 75=2units Vertex is at the mid point between Focus and Directrix. So vertex co-ordinate is (1,6) . The parabola opens down as focus is below the Vertex. We know the equation of parabola is y=a(xh)2+k where (h,k) is the vertex. Thus the Equation becomes y=a(x1)2+6 now a=14cwhere c is the distance between vertex and directrix; which is here equal to 1 so a=141=14 (negative sign is as the parabola opens down) So the equation becomes y=14(x1)2+6ory=14x2+12x+236graph{-1/4x^2+1/2x+23/6 [-10, 10, -5, 5]} [ans]